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public static void main(String[] args)throws IOException{
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer in = new StringTokenizer(br.readLine());
        PrintWriter out = new PrintWriter(new OutputStreamWriter(System.out));

        
            int t = Integer.parseInt(in.nextToken());

            for(int i=0;i<t;i++){
                in = new StringTokenizer(br.readLine());
                int n = Integer.parseInt(in.nextToken());

                int[] nums = new int[n];
                int count = 0;

                in = new StringTokenizer(br.readLine());
                for(int j=0;j<n;j++){
                    nums[j]=Integer.parseInt(in.nextToken());
                    count+=nums[j];
                }


                if(count%n!=0){
                    out.println("NO");
                }else{
                    /**
                     * 问题转化为：能否通过题目允许的操作，将所有偏差值变为0。
                     */
                    for(int j=0;j<n;j++){
                        nums[j]-=(count/n);
                    }

                    /**
                     * 将j-1位置的所有偏差值，全部累加到j+1位置，然后将j-1置为 0；
                     * 说人话就是模拟能量从左向右转移，清空左侧方碑的偏差。
                     */
                    for(int j =1;j<n-1;j++){
                        nums[j+1]+=nums[j-1];
                        nums[j-1]=0;
                    }

                    boolean flag = true;


                    for(int j=0;j<n;j++){
                        if(nums[j]!=0){
                            flag=false;
                            break;
                        }

                    }
                    out.println(flag?"YES":"NO");
                }
            }
        
        out.flush();
        out.close();
        br.close();
   }