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BISHI30 二进制数1

在这里插入图片描述

求解代码

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public static void main(String[] args) throws IOException {

        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));


        PrintWriter out = new PrintWriter(new OutputStreamWriter(System.out));

        String str = br.readLine();
        long n =Long.parseLong(str.trim());

        int count = 0;
        while (n > 0) {
            count += n & 1;
            n = n >> 1;
        }
        out.println(count);

        out.flush();
        out.close();
        br.close();
    }

小贴士

StreamTokenizerin.nvaldouble 类型(64 位浮点数), 但 double 的有效整数精度只有 53 位,将其强转为 long(64 位整数)会造成精度丢失,所以这里需要用BufferedReader.readLine()读取字符串再转 long

最后更新于 2026-04-05 17:35:33
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